Answer:
Object is thrown with a velocity of 56.74 m/sec
Step-by-step explanation:
We have given height h = 50 feet
When the object reach at its maximum height its final velocity will be o
So final velocity v = 0 m/sec
Acceleration due to gravity [tex]g=-32.2feet/sec^2[/tex] ( Negative sign is due to upward direction )
From third equation of motion
[tex]v^2=u^2+2gh[/tex]
[tex]0^2=u^2-2\times 32.2\times 50[/tex]
[tex]u^2=3220[/tex]
[tex]u=56.74m/sec[/tex]
So object is thrown with a velocity of 56.74 m/sec
Answer:
40 ft/sec
Step-by-step explanation:
height h = 50 ft
final velocity v would be zero.
acceleration a = -32 ft/sec^2
we kn that
u^2=v^2+2ah
u^2= 0^2- 32×50
u= √(32×50)
u= 40 ft/sec
the object must be thrown with the velocity of 40 ft/sec
