Answer:
V = 7.95 mL
Explanation:
We have in the 50 mL vial the next quantity of CaCO₃:
[tex] mEq CaCO_{3} = 4.4 \frac{mEq}{mL} \cdot 50 mL = 220 mEq [/tex]
Knowing that in 50 mL we have 220 mEq of CaCO₃, to have 35 mEq we need the following volume of the concentrate (Vc):
[tex] V_{c} = \frac{50 mL}{220 mEq} \cdot 35 mEq = 7.95 mL [/tex]
Therefore, for the addition of 35 mEq to the IV order, we need 7.95 mL of the concentrate 4.4 mEq/mL of CaCO₃.
I hope it helps you!
