Answer:
The values for the given function f is defined by [tex]f(x)=\frac{1}{2}x[/tex] is
a) [tex]f(0)=0[/tex] ,
b) [tex]f(18)=9[/tex] and
c) [tex]f(-18)=-9[/tex]
Step-by-step explanation:
Given that the function f is defined by [tex]f(x)=\frac{1}{2}x[/tex]
Now to find the value of f(0), f(18) and f(-18)
Now take f(0)
Put x=0 in the given function [tex]f(x)=\frac{1}{2}x[/tex] we get
[tex]f(0)=\frac{1}{2}(0)[/tex]
[tex]=0[/tex]
Therefore [tex]f(0)=0[/tex]
Put x=18 in the given function [tex]f(x)=\frac{1}{2}x[/tex] we get
[tex]f(18)=\frac{1}{2}(18)[/tex]
[tex]=9[/tex]
Therefore [tex]f(18)=9[/tex]
Put x=-18 in the given function [tex]f(x)=\frac{1}{2}x[/tex] we get
[tex]f(-18)=\frac{1}{2}(-18)[/tex]
[tex]=-9[/tex]
Therefore [tex]f(-18)=-9[/tex]
The values for the given function f is
a) [tex]f(0)=0[/tex] ,
b) [tex]f(18)=9[/tex] and
c) [tex]f(-18)=-9[/tex]
Answer:
The value of given function
A) f(0) = 0
B) f(18) = 9
C) f( - 18) = - 9
Step-by-step explanation:
Given as :
The function of x is given as
f(x) = [tex]\dfrac{x}{2}[/tex]
So, for every value of x , the value of function of x changes
A) for x = 0
f(0) = [tex]\dfrac{0}{2}[/tex]
i.e f(0) = 0
B) for x = 18
f(18) = [tex]\dfrac{18}{2}[/tex]
i.e f(18) = 9
C) for x = - 18
f( -18) = [tex]\dfrac{ -18}{2}[/tex]
i.e f(-18) = - 9
So, The value of f(0) = 0 , f(18) = 9 , f( - 18) = - 9
Hence, The value of given function
A) f(0) = 0
B) f(18) = 9
C) f( - 18) = - 9 Answer
