Answer:
The solution to the given system of equations is
([tex]-\frac{16}{5}[/tex],[tex]-\frac{21}{20}[/tex])
Step-by-step explanation:
Given system of equation are
[tex]6x-4y=-15\hfill (1)[/tex]
[tex]x-4y=1\hfill (2)[/tex]
To solve equation by using elimination method
Now subtracting equations (1) and (2)
[tex]6x-4y=-15[/tex]
[tex]x-4y=1[/tex]
_________________
5x=-16
[tex]x=-\frac{16}{5}[/tex]
Substitute [tex]x=-\frac{16}{5}[/tex] in equation (1)
[tex]6(-\frac{16}{5})-4y=-15[/tex]
[tex]-\frac{96}{5}-4y=-15[/tex]
[tex]-4y=-15+\frac{96}{5}[/tex]
[tex]-4y=\frac{21}{5}[/tex]
[tex]y=-\frac{21}{20}[/tex]
Therefore the solution is
([tex]-\frac{16}{5}[/tex],[tex]-\frac{21}{20}[/tex])
