Answer:
[tex]\large \boxed{134 \, ^{\circ}\text{C}}[/tex]
Explanation:
1. Calculate the temperature drop
[tex]\text{Temperature drop} = \text{4 h} \times \dfrac{11 \,^{\circ}\text{C}}{\text{1 h}} = 44 \,^{\circ}\text{C}[/tex]
2. Calculate the original temperature
[tex]\begin{array}{rcl}\text{Final Temperature} & = & \text{original temperature - temperature drop}\\90 ^{\circ}\text{C} & = & \text{original temperature - 44} \, ^{\circ}\text{C}\\\text{Original temperature}& = & \mathbf{134 \, ^{\circ}}\textbf{C}\\\end{array}\\\text{The original temperature was $\large \boxed{\mathbf{134 \, ^{\circ}}\textbf{C}}$}[/tex]
