Respuesta :
0.9750
Step-by-step explanation:
Given data: Normally distributed mean = 63.6 inches, standard deviation = 2.5 inches
Number of women, N = 150, Mean height = 64.0 inches
We know that [tex]Z=\frac{\bar{X}-\mu}{\frac{\sigma}{\sqrt{n}}}[/tex]
Now, [tex]P(\bar{X}>64)=P\left(\frac{\bar{X}-\mu}{\frac{\sigma}{\sqrt{n}}}>\frac{64.0-63.6}{\frac{2.5}{\sqrt{150}}}\right)[/tex]
= P(Z > 1.959)
= P(Z > 1.96) (Rounding off the 1.959 we get 1.96)
In the normal table look row wise 1.9 and column wise 0.06,
We get the value 0.9750.
Hence, [tex]P(\bar{X}>64)[/tex] = 0.9750.
Answer: 0.0250
Step-by-step explanation:
just took the test and missed it. Correct answer is 0.0250
