The polynomial of degree 5, P ( x ) has leading coefficient 1, has roots of multiplicity 2 at x = 2 and x = 0 , and a root of multiplicity 1 at x = āˆ’ 4 Find a possible formula for P ( x ) .

Respuesta :

Answer:

[tex]P(x)=x^5 - 12 x^3 + 16 x^2[/tex]

Step-by-step explanation:

P ( x ) has leading coefficient 1

Root of multiplicity n at x= a can be written in factor form (x-a)^n

Roots of multiplicity 2 at x = 2

[tex](x-2)^2[/tex]

Roots of multiplicity 2 at x = 0

[tex](x-0)^2[/tex] is [tex]x^2[/tex]

Roots of multiplicity 1 at x = -4

[tex](x-(-4))^1[/tex] is [tex]x+4[/tex]

multiply all the factors

[tex]P(x)= (x-2)^2 \cdot x^2 \cdot (x+4)[/tex]

[tex]P(x)= x^2(x-2)^2 (x+4)[/tex]

[tex]P(x)= x^2(x^2-4x+4) (x+4)[/tex]

[tex]P(x)=x^5 - 12 x^3 + 16 x^2[/tex]