Answer:
F = 266.67 N
Explanation:
given,
mass of the baseball = 0.5 Kg
speed of the baseball = 40 m/s
total displacement of the pitchers hand = 1 + 0.5 = 1.5 m
average force applied by the pitcher = ?
we know,
Work done is equal to change in kinetic energy, wheres as the initial velocity of the ball is zero.
W = KE
we know work done is equal to Force x displacement
[tex]F .s = \dfrac{1}{2}mv^2[/tex]
[tex]F\times 1.5 = \dfrac{1}{2}\times 0.5 \times 40^2[/tex]
F x 1.5 = 400
F = 266.67 N
the average force being applied by the pitcher is equal to F = 266.67 N
