A sample of blood pressure measurements is taken for a group of adults, and those values (mm Hg) are listed below. The values are matched so that 10 subjects each have a systolic and diastolic measurement. Find the coefficient of variation for each of the two samples; then compare the variation.

So for this case we have more variation for the data of systolic on left compared to the data systolic on right but the difference is not big since 0.170-0.147 = 0.023.

Step-by-step explanation:

Assuming the following data:

Systolic (#'s on right) Diastolic (#'s on left)

117; 80

126; 77

158; 76

96; 51

157; 90

122; 89

116; 60

134; 64

127; 72

122; 83

The coefficient of variation is defined as " a statistical measure of the dispersion of data points in a data series around the mean" and is defined as:

[tex] CV= \frac{\sigma}{\mu}[/tex]

And the best estimator is [tex]\hat {CV} =\frac{s}{\bar x}[/tex]

Systolic on right

We can calculate the mean and deviation with the following formulas:

[te]\bar x = \frac{\sum_{i=1}^n X_i}{n}[/tex]

[tex] s= \frac{\sum_{i=1}^n (x_i -\bar X)^2}{n-1}[/tex]

For this case we have the following values:

[tex] \bar x = 127.5, s= 18.68[/tex]

So then the coeffcient of variation is given by:

[tex] \hat{CV} =\frac{18.68}{127.5}=0.147[/tex]

Systolic on left

For this case we have the following values:

[tex] \bar x = 74.2 s= 12.65[/tex]

So then the coeffcient of variation is given by:

[tex] \hat{CV} =\frac{12.65}{74.2}=0.170[/tex]

So for this case we have more variation for the data of systolic on left compared to the data systolic on right but the difference is not big since 0.170-0.147 = 0.023.