Answer:
Explanation:
angular velocity of second is given by
[tex]\omega_0=\frac{2\pi }{60}=\frac{\pi }{30}\ rad/s[/tex]
suppose clockwise motion is positive
It is given that second hand halt over a brief period of time
using
[tex]\omega =\omega _0+\alpha \cdot t[/tex]
[tex]\omega =final\ angular\ velocity[/tex]
[tex]\omega _0=initial\ angular\ velocity[/tex]
[tex]\alpha =angular\ acceleration[/tex]
[tex]t=time[/tex]
[tex]\alpha =-\frac{\omega _0}{t}[/tex]
[tex]\alpha =-\frac{\pi }{30t}\ rad/s^2[/tex]
so direction of angular acceleration is anti-clockwise(opposite to angular velocity) as it try to cease the motion