The cost of one shirt is 12.50 and cost of one pair of jeans is 24.75
Step-by-step explanation:
Let,
Cost of one shirt = x
Cost of pair of jeans = y
According to given statement;
4x+3y=124.25 Eqn 1
3x+5y=161.25 Eqn 2
Multiplying Eqn 1 by 3
[tex]3(4x+3y=124.25)\\12x+9y=372.75\ \ \ Eqn\ 3[/tex]
Multiplying Eqn 2 by 4
[tex]4(3x+5y=161.25)\\12x+20y=645\ \ \ Eqn\ 4[/tex]
Subtracting Eqn 3 from Eqn 4
[tex](12x+20y)-(12x+9y)=645-372.75\\12x+20y-12x-9y=272.25\\11y=272.25[/tex]
Dividing both sides by 11
[tex]\frac{11y}{11}=\frac{272.25}{11}\\y=24.75[/tex]
Putting 24.75 in Eqn 1
[tex]4x+3(24.75)=124.25\\4x+74.25=124.25\\4x=124.25-74.25\\4x=50[/tex]
Dividing both sides by 4
[tex]\frac{4x}{4}=\frac{50}{4}\\x=12.50[/tex]
The cost of one shirt is 12.50 and cost of one pair of jeans is 24.75
Keywords: linear equation, elimination method
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