Answer:
4i+j-2k
Step-by-step explanation:
The missing figure in this problem as been attached, as we can see the figure is a 3-D figure consisting of rods with point C and B.
Using the figure we can find the value of position vector [tex]r_{cb}[/tex]
r[tex]_{CB}[/tex]=[tex]r_{b}[/tex]-[tex]r_{c}[/tex]
As we know , a position vector is the difference of position vector of ending point to the position vector of starting point, here the starting point is C and ending point is B. Hence, the expression above.
We need to first find [tex]r_{b}[/tex] and [tex]r_{c}[/tex]
Using the figure:
[tex]r_{b}[/tex] =0i+4j+2k
[tex]r_{c}[/tex] = -4i+3j+4k
r[tex]_{CB}[/tex]=[tex]r_{b}[/tex]-[tex]r_{c}[/tex]=(0i+4j+2k) - (-4i+3j+4k)
r[tex]_{CB}[/tex]=4i+j-2k (feet)
Magnitude of [tex]r_{cb}[/tex]=[tex]\sqrt{4^{2}+(1)^{2}-2^{2} }[/tex]=[tex]\sqrt{21}[/tex]=4.583 ft