Answer:
The quality is 93%.
Explanation:
Given that,
Pressure = 0.005 MPa
Liquid water = 2%
Vapor water = 98%
We need to calculate the quality
Using formula of quality
[tex]quality=\dfrac{\text{Vapour water}\times\text{specific volume of liquid water at 0.005}}{\text{Liquidr water}\times\text{specific volume of vapour water at 0.005}}[/tex]
Put the value into the formula
[tex]quality=\dfrac{98\times0.0010}{5\times2.08719}[/tex]
[tex]quality=0.0093[/tex]
[tex]quality=0.0093\times100[/tex]
[tex]quality=93\%[/tex]
Hence, The quality is 93%.
