The values of A, J and W are 8, 9 and 1 respectively
Step-by-step explanation:
The given is:
We need to find them
∵ WJA is three digit-number
∴ A is the ones digit
∴ J is the tens digit
∴ W is the hundreds digit
- W must be 1 because the greatest sum of 2 different tens digits
is 17, 7 in the tens place and 1 in the hundreds place
∴ W = 1
∵ W digit must be equal 1
∴ 11 + JJ + AA = 1JA
- Add the ones digits and equate them by A + 10, because the
sum of them will give number greater than 9, so we will carry
one over the tens digit (1 tens = 10)
∵ A + J + W = A + 10
∵ W = 1
∴ A + J + 1 = A + 10
- Subtract A from both sides
∴ 1 + J = 10
- Subtract 1 from both sides
∴ J = 9
∴ 11 + 99 + AA = 19A
- Add the tens digits with carry 1 from the sum of the ones digit
and equate them by 19 (1 + A + J + W = 19)
∵ 1 + A + 9 + 1 = 19
- Add like terms in the left hand side
∴ A + 11 = 19
- Subtract 11 from both sides
∴ A = 8
- Lets check the answer
∵ 11 + 99 + 88 = (8 + 9 + 1) + (80 + 90 + 10)
∴ 11 + 99 + 88 = (10 + 8) + (100 + 80)
∴ 11 + 99 + 88 = 100 + (80 + 10) + 8
∴ 11 + 99 + 88 = 100 + 90 + 8 = 198
∴ A is 8 , J is 9 and W is 1
The values of A, J and W are 8, 9 and 1 respectively
Learn more:
You can learn more about the numbers in brainly.com/question/547255
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