Answer:
0.535
Step-by-step explanation:
Let students that attend homecoming = H
Let students that attend football game = F
Pr(H) = 43% = 0.43
Pr (H and F) = 23% = 0.23
For conditional probability,
Pr(H and F) = Pr(H) * Pr(H|F)
Pr(H|F) = Pr(H and F) / Pr(H)
=0.23/0.43
Pr(H|F) = 0.535
The probability that a student attends football game and also attends dance = 0.535