Answer:
(-6,-8),(7,18) and (-4,6),(2,3) lie on perpendicular lines
Step-by-step explanation:
we know that
The formula to calculate the slope between two points is equal to
[tex]m=\frac{y2-y1}{x2-x1}[/tex]
step 1
Find the slope of the pair (-6,-8),(7,18)
substitute
[tex]m=\frac{18+8}{7+6}[/tex]
[tex]m=\frac{26}{13}[/tex]
[tex]m=2[/tex]
step 2
Find the slope of the pair (6,4),(4,12)
substitute
[tex]m=\frac{12-4}{4-6}[/tex]
[tex]m=\frac{8}{-2}[/tex]
[tex]m=-4[/tex]
step 3
Find the slope of the pair (-4,6),(2,3)
substitute
[tex]m=\frac{3-6}{2+4}[/tex]
[tex]m=\frac{-3}{6}[/tex]
[tex]m=-\frac{1}{2}[/tex]
step 4
Remember that
If two lines are perpendicular, then their slopes are opposite reciprocal (the product of their slopes is equal to -1)
In this problem
[tex]m=2[/tex] and [tex]m=-\frac{1}{2}[/tex] are opposite reciprocal
therefore
(-6,-8),(7,18) and (-4,6),(2,3) lie on perpendicular lines
