Answer:
[tex]y'=7.36e^{0.23t}[/tex]
Step-by-step explanation:
[tex]y=32e^{0.23t}[/tex]
take derivative with respect to t
[tex]\frac{dy}{dt} =32\frac{d(e^{0.23t})}{dt}[/tex]
derivative of e^t is e^t
derivative of 0.23t is 0.23
[tex]\frac{dy}{dt} =32 \frac{d(e^{0.23t})}{dt}[/tex]
Apply chain rule
[tex]\frac{dy}{dt} =32(e^{0.23t})(0.23)[/tex]
[tex]y'=7.36e^{0.23t}[/tex]
