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An isosceles triangle (two sides equal) is placed on top of a square as shown in the picture. If the two equal sides of the triangle are 25m 25⁢m long and the square is 33m 33⁢m on each side, what is the perimeter of the figure?

Respuesta :

Answer:

The perimeter of figure is 215 meters .

Step-by-step explanation:

Given as :

An isosceles triangle (two sides equal) is placed on top of a square

The measure of each side of square = 33 meters

The measure of same two sides of isosceles triangle = 25 m

From figure

ABCD is a square with sides

AB = BC = CD = DA = 33 m

And

CDE is a isosceles triangle with sides

CD = 33 m

CE = ED = 25 m

Let The perimeter of figure = x meters

Again

The perimeter of figure = Perimeter of square + Perimeter of Triangle

∵ Perimeter of square = 4 × sides

So, Perimeter of square = 4 × 33 m

Or, Perimeter of square = 132 meters

And

∵ Perimeter of triangle = sum of measure of all sides

So, Perimeter of triangle = CD + DE + EC

Or, Perimeter of triangle = 33 m + 25 m + 25 m

Or, Perimeter of triangle = 83 meters

Now, The perimeter of figure = Perimeter of square + Perimeter of Triangle

So, x = 132 meters + 83 meters

Or, x = 215 meters

So, The Perimeter of figure = x = 215 meters

Hence, The perimeter of figure is 215 meters . Answer

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