Respuesta :

fredycopete

Answer:

92,259.73 Joules

Explanation:

α=12.5°

m=1000 kg

d= 45m

[tex]F=m*g*Sin(\alpha)\\[/tex]°)[tex]

F= 1000kg*9.81 \frac{m}{s} *Sin (12.5 )\\[/tex]

[tex]F= 1000 kg * 9.81 \frac{m}{s} * 0.2164\\[/tex]

[tex]F= 2,123.27 N\\[/tex]

[tex]W=F*d*Cos (\alpha)\\[/tex]

[tex]W= 2,123.27 N * 45m * Cos (12,5)\\[/tex]

[tex]W= 92,259.73   Joules[/tex]

onyebuchinnaji

The minimum work needed to push the car up the given height is 4.41 x 10⁵ J.

The given parameters;

  • mass of the car, m = 1000 kg
  • height up to the incline, h = 45 m
  • length of the incline, L = 12.5 m

Assuming no friction, the minimum work needed to push the car up the given height is calculated as follows;

W = mgh

W = 1000 x 9.8 x 45

W = 4.41 x 10⁵ J.

Thus, the minimum work needed to push the car up the given height is 4.41 x 10⁵ J.

Learn more here:https://brainly.com/question/6049893

Otras preguntas