Answer: The probability that the fruit is an orange or a pear is [tex]\dfrac{1}{3}[/tex] .
Step-by-step explanation:
Given : Emily has 12 fruits in her bowl.
She has 3 apples, 5 bananas, 1 pear and 3 oranges.
A fruit is selected at random.
P(orange) = [tex]\dfrac{\text{Number of oranges}}{\text{Total fruits}}[/tex]
[tex]=\dfrac{3}{12}[/tex]
P(pear)= [tex]\dfrac{\text{Number of pears}}{\text{Total fruits}}[/tex]
[tex]=\dfrac{1}{12}[/tex]
Since both events of selecting orange and pear are mutually exclusive , so
The probability that the fruit is an orange or a pear = P(orange) + P(pear)
[tex]=\dfrac{3}{12}+\dfrac{1}{12}=\dfrac{4}{12}=\dfrac{1}{3}[/tex]
Therefore , the probability that the fruit is an orange or a pear is [tex]\dfrac{1}{3}[/tex] .
