Answer:
1. no. of moles of Oxygen = 3687.5 mol
2. amount of CO₂ taken = 3687.5 moles
3. Option B is correct = 2.22 x 10²⁷
Explanation:
Data Given:
Amount of O₂ = 118 Kg
moles of O₂ = ?
no. of molecules of CO₂ = ?
Solution:
First we have to convert Kg to g
Convert unit from Kg to g
1 Kg = 1000 g
118 Kg = 118 x 1000 = 118000 g
Now we will find number of moles of O₂
Mole formula will be used
no. of moles = mass in grams/ molar mass
molar mass of O₂ = 2(16) = 32 g/mol
Put values in mole formula
no. of moles = 118000 g/ 32 g/mol
no. of moles = 3687.5 mol
So we have 3687.5 moles of Oxygen
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Part 2:
Now we have to find moles of CO₂ taken by plant to to produce 3687.5 moles of Oxygen
First we will look for the reaction by
6 CO₂ + 6 H₂O ---------> 6 C₆H₆O₆ + 6 O₂
So,
6 CO₂ + 6 H₂O ---------> 6 C₆H₆O₆ + 6 O₂
6 mole 6 mole
So from the above reaction we come to know that 6 moles of CO₂ will be taken to produce 6 moles of O₂
As we Know,
6 moles of CO₂ ≅ 6 moles of O₂
So,
3687.5 moles of CO₂ ≅ 3687.5 moles of O₂
So amount of CO₂ taken = 3687.5 moles
_________________________
Part 3
Now we will find number of molecules of CO₂
Mole formula will be used
no. of moles = no. of molecules / Avogadro's number
Rearrange the above formula
no. of molecules = no. of moles x Avogadro's number . . . . . (1)
Avogadro's number = 6.022 x 10²³
Put values in mole formula (1)
no. of molecules = 3687.5 moles x 6.022 x 10²³
no. of molecules = 2.22 x 10²⁷
So ,
Option B is correct = 2.22 x 10²⁷
