Answer:
A) 100 mL
Explanation:
At constant temperature and number of moles, Using Boyle's law
[tex]{P_1}\times {V_1}={P_2}\times {V_2}[/tex]
Given ,
V₁ = 200 mL
V₂ = ?
P₁ = 60 kPa
P₂ = 120 kPa
Using above equation as:
[tex]{P_1}\times {V_1}={P_2}\times {V_2}[/tex]
[tex]{60\ kPa}\times {200\ mL}={120\ kPa}\times {V_2}[/tex]
[tex]{V_2}=\frac{{60}\times {200}}{120}\ mL[/tex]
[tex]{V_2}=100\ mL[/tex]
The new volume of the gas is 100 mL
The correct answer to the question is Option A. 100 mL
From the question given above, the following data were obtained:
Initial pressure (P₁) = 60 KPa
Initial volume (V₁) = 200 mL
Final pressure (P₂) = 120 KPa
Temperature = constant
P₁V₁ = P₂V₂
60 × 200 = 120 × V₂
12000 = 120 × V₂
Divide both side by 120
V₂ = 12000 / 120
Therefore, the new volume of the gas is 100 mL
The correct answer to the question is Option A. 100 mL
Learn more: https://brainly.com/question/23558057
