Respuesta :
The number of tungsten Atoms in a typical light bulb filament is
5.76 × [tex]10^{19}[/tex] atoms of W
Explanation:
Write the given values of the problem
The diameter the tungsten wire in a light bulb filament Tungsten element W : molar mass = 183.84 g / mol
0.0176 g W × [tex]\frac{1mol}{183.84 g}[/tex] = 0.000096 mol W
0.000096 mol W × [tex]\frac{6.02 × [tex]10^{23 atoms}[/tex]}{1 mol W}[/tex]
= 5.76 × [tex]10^{19}[/tex] atoms of W
A typical lightbulb filament, whose mass is 0.0176 g, contains 5.76 × 10¹⁹ atoms of tungsten.
The mass of a typical lightbulb filament of tungsten is 0.0176 grams. We can convert 0.0176 g to moles using the molar mass of tungsten (183.84 g/mol).
[tex]0.0176 g \times \frac{1mol}{183.84g} = 9.57 \times 10^{-5} mol[/tex]
To convert 9.57 × 10⁻⁵ mol to atoms, we will use Avogadro's number: there are 6.02 × 10²³ atoms in 1 mole of atoms.
[tex]9.57 \times 10^{-5} mol \times \frac{6.02 \times 10^{23}atom }{1mol} = 5.76 \times 10^{19}atom[/tex]
A typical lightbulb filament, whose mass is 0.0176 g, contains 5.76 × 10¹⁹ atoms of tungsten.
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