The stopping distance is 50 m
Explanation:
First of all, we calculate the acceleration of the car, which is given by Newton's second law:
[tex]a=\frac{F}{m}[/tex]
where
F = -3000 N is the force applied on the car
m = 3000 kg is the mass of the car
Substituting,
[tex]a=\frac{-3000}{3000}=-1 m/s^2[/tex]
Now we can use the following suvat equation, since this is a uniformly accelerated motion:
[tex]v^2-u^2=2as[/tex]
where
v = 0 is the final velocity of the car
u = 10 m/s is the initial velocity
[tex]a=-1 m/s^2[/tex] is the acceleration
s is the distance travelled by the car (the stopping distance)
Solving for s, we find
[tex]s=\frac{v^2-u^2}{2a}=\frac{0-10^2}{2(-1)}=50 m[/tex]
Learn more about accelerated motion:
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