Answer:
[tex](lnx(x + 1)^{\frac{1}{4}})^2[/tex]
Step-by-step explanation:
[tex]2[ln x +\frac{1}{4}ln(x + 1)][/tex]
m ln(n)= ln(n)^m
we move the term before ln to the exponent
[tex]2[ln x +ln(x + 1)^{\frac{1}{4}}][/tex]
[tex]ln m +ln n = ln(mn)[/tex]
[tex]2[ln x +ln(x + 1)^{\frac{1}{4}}][/tex]
[tex]2[ln(x(x + 1)^{\frac{1}{4}})][/tex]
as per log property , move 2 to the exponent
[tex](lnx(x + 1)^{\frac{1}{4}})^2[/tex]
