The slope of the line containing the points (-6, 1) and (5, 3) is [tex]\frac{2}{11}[/tex]
Solution:
Given that we have to find the slope of the line containing the points (-6, 1) and (5, 3)
[tex]\text{The slope of points } (x_1, y_1) \text{ and } (x_2, y_2) \text{ is given by: }[/tex]
[tex]m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}[/tex]
Here in this question,
[tex](x_1, y_1) = (-6, 1)\\\\(x_2, y_2) = (5, 3)[/tex]
Substitute the values in above mentioned formula,
[tex]m = \frac{3-1}{5-(-6)}[/tex]
Simplify the above expression
[tex]m = \frac{2}{5+6}\\\\m = \frac{2}{11}[/tex]
Thus the slope of the line containing the points (-6, 1) and (5, 3) is [tex]\frac{2}{11}[/tex]
