Answer:
1.9311 m/s
168.86792 N
Explanation:
v = Final velocity
m = Mass of truck = [tex]2.4\times 10^3\ kg[/tex]
s = Displacement = 26.5 m
Work done is given by
[tex]W=\dfrac{1}{2}m(v^2-u^2)\\\Rightarrow W=\dfrac{1}{2}m(v^2-0^2)\\\Rightarrow v=\sqrt{\dfrac{2W}{m}}\\\Rightarrow v=\sqrt{\dfrac{2\times 4475}{2.4\times 10^3}}\\\Rightarrow v=1.9311\ m/s[/tex]
The speed is 1.9311 m/s
Work done is given by
[tex]W=Fs\\\Rightarrow F=\dfrac{W}{s}\\\Rightarrow F=\dfrac{4475}{26.5}\\\Rightarrow F=168.86792\ N[/tex]
The horizontal force is 168.86792 N
