Answer:
[tex]T=2\pi \times \sqrt {\frac {g}{\mu R}[/tex]
Explanation:
[tex]\mu mw^{2}R=mg[/tex]
where m is the mass, g is acceleration due to gravity
The masses m are on both sides hence they cancel
[tex]W=\sqrt {\frac {g}{\mu R}[/tex]
We know that T=2\pi W and substituting W with the above equation then
[tex]T=2\pi \times \sqrt {\frac {g}{\mu R}[/tex]
