Answer: There will be 22.694 grams of initial mass remains after 50 years.
Step-by-step explanation:
Since we have given that
[tex]y=35(\dfrac{1}{2})^{\frac{t}{80}[/tex]
We need to find the quantity of initial mass remains after 50 years.
So, t = 50 years,
We get that
[tex]y=35(\dfrac{1}{2})^{\frac{50}{80}}\\\\y=35(0.5)^{0.625}\\\\y=22.694[/tex]
Hence, there will be 22.694 grams of initial mass remains after 50 years.