Answer:
P(A) = 0.49
Step-by-step explanation:
Given:
A and B are mutually exclusive events.
P(B) = 0.03
P(A or B) = 0.52
If two events A and B are mutually exclusive events, then there are no elements common in both the events. So, the probability of their intersection is 0.
Now, as per probability addition theorem:
P(A or B) = P(A) + P(B) + P(A and B)
For mutually exclusive events, P(A and B) = 0. So,
P(A or B) = P(A) + P(B) + 0
P(A or B) = P(A) + P(B)
Plug in the given values and solve for P(A). This gives,
0.52 = P(A) + 0.03
P(A) = 0.52 - 0.03
P(A) = 0.49
Therefore, the probability of occurrence of event A is P(A) = 0.49.
