The cost of 1 hamburger is $ 2.5 and cost of 1 fries is $ 0.8
Let "f" be the cost of 1 fries
Let "h" be the cost of 1 hamburger
Given that, tennis coach took his team out for lunch and bought 8 hamburgers and 5 fries for $24
8 x cost of 1 hamburger + 5 x cost of 1 fries = 24
[tex]8 \times h + 5 \times f = 24[/tex]
8h + 5f = 24 -------- eqn 1
The players were still hungry so the coach bought six more hamburgers and two more fries for $16.60
6 x cost of 1 hamburger + 2 x cost of 1 fries = 16.60
[tex]6 \times h + 2 \times f = 16.60[/tex]
6h + 2f = 16.60 ------ eqn 2
Let us solve eqn 1 and eqn 2
Multiply eqn 1 by 2
16h + 10f = 48 ------ eqn 3
Multiply eqn 2 by 5
30h + 10f = 83 -------- eqn 4
Subtract eqn 3 from eqn 4
30h + 10f = 83
16h + 10f = 48
( - ) ----------------------
14h = 35
Substitute h = 2.5 in eqn 1
8(2.5) + 5f = 24
20 + 5f = 24
5f = 4
Thus cost of 1 hamburger is $ 2.5 and cost of 1 fries is $ 0.8
