We have 10 blocks, of which 5 are green, 3 are red, 1 is white, and 1 is black. If we put the blocks in a line, how many arrangements are possible?

Respuesta :

Answer:

5040 ways

Step-by-step explanation:

Since there are 10 blocks,

It can be arranged in 10! ways

But there is 5 green,3 red, 1 white and 1 black blocks.

Therefore, the blocks can be arranged in 10!/(5!*3!*1!*1!) ways

= 5040 ways

There are 5040 ways of possible arrangements, If we put the blocks in a line.

Given that,

We have 10 blocks, of which 5 are green, 3 are red, 1 is white, and 1 is black.

We have to determine,

If we put the blocks in a line, how many arrangements are possible?

According to the question,

Total number of blocks = 10

Number of green blocks = 5

Number of red blocks = 3

Number of white blocks = 1

Number of black blocks = 1

Then,

If we put the blocks in a line, the number of possible arrangements is,

[tex]\rm Number \ of \ possible \ arrangement = \dfrac{Total \ number \ of \ blocks}{ Green \times red \times black \times \ white }[/tex]

Substitute all the values in the formula,

[tex]\rm Number \ of \ possible \ arrangement = \dfrac{10!}{ 5!\times 3! \times 1! \times \ 1! }\\\\ Number \ of \ possible \ arrangement =\dfrac{3628800}{120 \times 6 \times 1\times1 }\\\\ Number \ of \ possible \ arrangement =5040[/tex]

Hence, there are 5040 ways of possible arrangements, If we put the blocks in a line.

For more details refer to the link given below.

https://brainly.com/question/11732255