Answer:
5 N
Explanation:
[tex]F_1[/tex] = 20 N
[tex]r_1[/tex] = 6 cm
[tex]r_2[/tex] = 12 cm
k = Coulomb constat
q = Charge
[tex]\dfrac{F_1}{F_2}=\dfrac{\dfrac{kq_1q_2}{r_1^2}}{\dfrac{kq_2q_2}{r_2^2}}\\\Rightarrow \dfrac{F_1}{F_2}=\dfrac{r_2^2}{r_1^2}\\\Rightarrow \dfrac{F_1}{F_2}=\dfrac{12^2}{6^2}\\\Rightarrow \dfrac{F_1}{F_2}=4\\\Rightarrow F_2=\dfrac{F_1}{4}\\\Rightarrow F_2=\dfrac{20}{4}\\\Rightarrow F_2=5\ N[/tex]
The force is 5 N
