Find the volume of the solid of revolution formed by rotating about the x--axis the region bounded by the given curves.
f(x)=x2, y=0, x=1, x=5.

Respuesta :

Answer:

624.8 pi

Step-by-step explanation:

Given that a parabola open up with original as vertex is rotated about x axis

LImits for x are 1 and 5

y = x^2 is the parabola

We have volume when rotated about x axis is

[tex]\pi \int\limits^a_b {y^2} \, dx[/tex]

Here lower limit = 1 and higher limit = 5

[tex]\pi \int\limits^5_1 {y^2} \, dx \\=\pi \int\limits^5_1 {x^4} \, dx \\=\pi (\frac{x^5}{5} )_1^5\\=\pi (\frac{1}{5} )(5^5-1^5)\\= 624.8 \pi[/tex]

Volume generated = 624.8 pi