Answer:
[tex]4\pi\ln4[/tex]
Step-by-step explanation:
We are given: [tex]f(x)=\frac{2}{\sqrt{x+2}}[/tex]
The volume will be calculated with integral.
[tex]V = \pi\int\limits^2_{-1}(f(x))^2dx=\pi\int\limits^2_{-1}\frac{4}{x+2}dx=4\pi\ln(x+2)|^2_{-1}=4\pi\ln4[/tex]
