Answer:
Therefore Surface Area of the Pyramid is 736 cm².
Step-by-step explanation:
Given:
Square Pyramid,
Base = 16 cm = side of Square
Altitude of Triangular part = 15 cm
To Find:
Surface Area of the Pyramid = ?
Solution:
Surface Area of the Pyramid will be given as
[tex]\textrm{Surface Area of the Pyramid}=\textrm{Area of Square base}+4\times \textrm{Area of Triangle}[/tex]
Now for Area of Square,
[tex]\textrm{Area of Square base}=Base\times Base[/tex]
Substituting the values we get
[tex]\textrm{Area of Square base}=16\times 16=256\ cm^{2}[/tex]
Now for Area of Triangle we have,
[tex]\textrm{Area of the Triangle } = \dfrac{1}{2}\times Base\times Altitude[/tex]
Substituting the values we get
[tex]\textrm{Area of the Triangle} = \dfrac{1}{2}\times 16\times 15=120\ cm^{2}[/tex]
Now Substituting Area of Square and Area of the Triangle in Surface area we get,
[tex]\textrm{Surface Area of the Pyramid}=256+4\times 120=736\ cm^{2}[/tex]
Therefore Surface Area of the Pyramid is 736 cm².
