Which set of compounds illustrates the Law of Multiple Proportions?
NO, NH3,
NH4Cl, CH4
C2H6, C3H8
H2O, H2
all of these

Respuesta :

Answer : The sets of compound that show the Law of Multiple Proportions are, [tex]CH_4,C_2H_6\text{ and }C_3H_8[/tex]

Explanation :

Law of multiple proportion : It states that when two elements can combine to form two or more different compounds then the mass of one element compared to fixed mass of the other will always be in a ratio of small whole numbers.

As per given options, [tex]CH_4,C_2H_6\text{ and }C_3H_8[/tex] are the sets of compound that show the Law of Multiple Proportions because these are the different compounds which is formed by the two elements.

As per given options, [tex]NO,NH_3\text{ and }NH_4Cl[/tex] and [tex]H_2O\text{ and }H_2[/tex] are not the sets of compound that show the Law of Multiple Proportions because these are the different compounds which is formed by the two different elements.

Ratio of C and H in [tex]CH_4[/tex] = 1 : 4

Ratio of C and H in [tex]C_2H_6[/tex] = 2 : 6

Ratio of C and H in [tex]C_3H_8[/tex] = 3 : 8

Now we have to determine the mass ratio of hydrogen by fixing the mass of carbon.

In [tex]CH_4[/tex], 12 g of carbon combine with 4 g of hydrogen.

As in [tex]C_2H_6[/tex], 24 g pf carbon combine with 6 g of hydrogen

So, 12 g of carbon combine with [tex]\frac{12}{24}\times 6=3g[/tex] of hydrogen

and,

As in [tex]C_3H_8[/tex], 36 g pf carbon combine with 8 g of hydrogen

So, 12 g of carbon combine with [tex]\frac{12}{36}\times 8=\frac{8}{3}g[/tex] of hydrogen

Thus, the mass of ratio of hydrogens are:

[tex]4:3:\frac{8}{3}[/tex]

To make in a whole number we are multiplying the ratio by 3, we get:

[tex]4\times 3:3\times 3:\frac{8}{3}\times 3[/tex]

[tex]12:9:8[/tex]

That means, when two elements can combine to form two or more different compounds then the mass of one element compared to fixed mass of the other will always be in a ratio of small whole numbers.

Hence, the sets of compound that show the Law of Multiple Proportions are, [tex]CH_4,C_2H_6\text{ and }C_3H_8[/tex]

The set of compounds which illustrates the Law of Multiple Proportions are

CH4, C2H6, C3H8.

The law of multiple proportion states that if two elements form two or more

compounds, the ratios of the masses of the second element combining with

the first element which will have a fixed mass will always be ratios of small

whole numbers.

The most appropriate option which depicts it is  CH4, C2H6, C3H8. They

comprise of two elements and the ratio of their masses is in small

whole numbers

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