Analyzing a Graph In Exercise, analyze and sketch the graph of the function. Label any relative extrema, points of inflection, and asymptotes.
y = In(x + 3)

So first we need to take the first derivative to find the interval of increase and decrease, then the second derivative to find the interval of concave up and concave down.

[tex]y'=\frac{1}{x+3}[/tex]

[tex]y''=-\frac{1}{(x+3)^2}[/tex]

So it is always increasing function, and always concave down function.

Since it is a logarithmic function, x>3.

So, x = 3 is vertical asymptote.

I attached the sketch as a picture.

Analyzing a Graph In Exercise, analyze and sketch the graph of the function. Label any relative extrema, points of inflection, and asymptotes. y = In(x + 3)

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Analyzing a Graph In Exercise, analyze and sketch the graph of the function. Label any relative extrema, points of inflection, and asymptotes.
y = In(x + 3)