Answer:
[tex](2x - 3y)(x + 2)[/tex]
Step-by-step explanation:
We want to factor
[tex]2 {x}^{2} - 3xy - 6y + 4x[/tex]
We regroup to obtain
[tex]2 {x}^{2} + 4x - 3xy - 6y[/tex]
We factor to get:
[tex]2x(x + 2) - 3y(x + 2)[/tex]
We collect a common factor of x+2 to obtain:
(2x-3y)(x+2)
Therefore the completely factored form is
[tex]2 {x}^{2} - 3xy - 6y + 4 = (2x - 3y)(x + 2)[/tex]
