Answer:
5
Step-by-step explanation:
[tex]log_2{32}[/tex]
write 32 in exponential form
32 = 2 times 2 times 2 times 2 times 2
32= 2^5
[tex]log_2{32}[/tex]
[tex]log_2{2^5}[/tex]
As per log property move the exponent before log
[tex]log_2{2^5}[/tex]
[tex]5log_2{2}[/tex]
both log base and log term are same , log_a(a)=1
[tex]5log_2{2}[/tex]
[tex]5(1)[/tex]
5
