Find the general solution for the differential equation \displaystyle{\left.{d}{y}\right.}+{9}{x}\ {\left.{d}{x}\right.}={0}dy+9x dx=0 CC, a constant of integration

Respuesta :

Answer:

y= CC-4.5x^2

Step-by-step explanation:

To find the general solution to the differential equation

dy + 9x dx = 0, we employ the method of separating variable as follows:

Note: { will represent the integral sign here.

Separating the variables and integrating, we have

{dy  = -{9x dx

y = -(9/2)(x^2) + CC,

where CC is the given constant of integration.

This can be rearranged/simplified to yield

y= CC-4.5x^2

The general solution of equation  [tex]\displaystyle{\left.{d}{y}\right.}+{9}{x}\ {\left.{d}{x}\right.}={0}\\[/tex] is  [tex]y=-4.5x^{2} +C[/tex].

Given, differential equation is,

[tex]\displaystyle{\left.{d}{y}\right.}+{9}{x}\ {\left.{d}{x}\right.}={0}\\[/tex].

We have to find the solution of this equation.

On separating the variables of the differential equation, we get

[tex]dy= -9x \ dx[/tex]

Now integrating both sides, we get

[tex]\int\ {} \, dy=\int\ {-9x} \, dx +C[/tex] , here C is the constant of integration.

[tex]y=-9\int\ {x} \, dx +C\\y=-9\frac{x^{2} }{2} +C[/tex]

[tex]y=-4.5x^{2} +C[/tex]

Hence the general solution of equation  [tex]\displaystyle{\left.{d}{y}\right.}+{9}{x}\ {\left.{d}{x}\right.}={0}\\[/tex] is  [tex]y=-4.5x^{2} +C[/tex].

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