Answer:
[tex]\rho=11300\ kg/m^3[/tex]
Explanation:
given,
Volume of the Joey treasure chest = 1.5 m³
mass of the coin = 16,950 Kg
density of the metal of the coins = ?
we know,
[tex]density=\dfrac{mass}{volume}[/tex]
[tex]\rho=\dfrac{m}{v}[/tex]
[tex]\rho=\dfrac{16950}{1.5}[/tex]
[tex]\rho=11300\ kg/m^3[/tex]
the density to determine the metal of the coins is equal to [tex]\rho=11300\ kg/m^3[/tex]