Answer:
Grayson has to walk 1.7 miles across the field.
Step-by-step explanation:
We have drawn the diagram for your reference.
Given:
Grayson usually walks 1.5 miles west on the side walks
According to Diagram we can say;
CA = 1.5 miles
Also Given:
Grayson also walks 0.8 miles north on the sidewalks
So According to Diagram we can say;
BA =0.8 miles
Now we need to find number of miles Grayson have to walk across the field.
According to diagram we can say;
We have to find CA.
Assuming the diagram to be right angled triangle.
We can find CA using Pythagoras theorem.
[tex]{CA}^2 = {CB}^2+{BA}^2[/tex]
Substituting the given values we get;
[tex]{CA}^2 =1.5^2+0.8^2 = 2.25 +0.64 =2.89[/tex]
Taking square root on both side we get;
[tex]\sqrt{{CA}^2} = \sqrt{2.89} \\\\CA = 1.7 \ mi[/tex]
Hence Grayson has to walk 1.7 miles across the field.
