An airplane travels 460 miles from San Diego to San Francisco in 2.5 hours, going against the wind. The return trip is with the wind, and takes only 2 hours. Find the rate of the airplane with no wind. Find the rate of the wind.

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Answer:

The speed of airplane is 207 miles per hour

The speed of wind is 23 miles per hour  

Step-by-step explanation:

Given as :

The distance cover by airplane against the wind = D = 460 miles

The time taken to cover D distance = T = 2.5 hours

Again

The distance cover by airplane with the wind = d = 460 miles

The time taken to cover d distance = t = 2 hours

Let The speed of airplane = x mile per hour

Let The speed of wind = y miles per hour

According to question

Speed = [tex]\dfrac{\textrm Distance}{\textrm Time}[/tex]

For Against the wind

x - y =   [tex]\dfrac{\textrm D}{\textrm T}[/tex]

Or, x - y =   [tex]\dfrac{\textrm 460 miles}{\textrm 2.5 hours}[/tex]

Or, x - y = 184 mph        ........1

For with the wind

x + y =   [tex]\dfrac{\textrm d}{\textrm t}[/tex]

Or, x + y =   [tex]\dfrac{\textrm 460 miles}{\textrm 2 hours}[/tex]

Or, x + y = 230 mph        ........2

Now, Solving eq 1 and eq 2

(x - y) + (x + y) = 184 mph + 230 mph

Or, (x + x) + ( - y + y) = 414 mph

Or, 2 x + 0 = 414 mph

∴  x = [tex]\dfrac{414}{2}[/tex]

i,e x = 207 mph

So, The speed of airplane = x = 207 miles per hour

Now, Put the value of x into eq 1

∵  x - y = 184 mph

So, 207 mph - y = 184 mph

Or, y = 207 mph - 184 mph

i.e y = 23 mph

So, The speed of wind = y = 23 miles per hour  

Hence, The speed of airplane is 207 miles per hour and The speed of wind is 23 miles per hour   . Answer

Answer:

The airplane flies at 207 mi/h with no wind. The rate of the wind is 23 mi/h.