A sample of neon gas exerts a pressure of 120 kPa when the temperature is 400 K. What pressure is produced when the temperature is raised to 600 K?

Respuesta :

The final pressure of the gas is 180 kPa

Explanation:

Assuming that the volume of the gas remains the same, we can use Charle's law, which states that:

"For a gas at fixed volume, the pressure of the gas is directly proportional to its absolute temperature"

Mathematically,

[tex]\frac{p}{T}=const.[/tex]

where

p is the pressure of the gas

T is its temperature in Kelvin

The equation can also be rewritten as

[tex]\frac{p_1}{V_1}=\frac{p_2}{V_2}[/tex]

For the sample of neon gas in this problem, we have:

[tex]p_1 = 120 kPa[/tex] (initial pressure)

[tex]T_1 = 400 K[/tex] (initial temperature)

[tex]T_2 = 600 K[/tex] (final temperature)

By solving the equation, we can find the final pressure, [tex]p_2[/tex]:

[tex]p_2 = \frac{p_1 T_2}{T_1}=\frac{(120)(600)}{400}=180 kPa[/tex]

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