The work done on the ship is [tex]1.5\cdot 10^7 J[/tex]
Explanation:
The work done by a force on an object is given by:
[tex]W=Fd cos \theta[/tex]
where
F is the magnitude of the force
d is the displacement
[tex]\theta[/tex] is the angle between the direction of the force and of the displacement
In this problem, we have:
[tex]F=5.00\cdot 10^3 N[/tex] (force acting on the ship)
d = 3.00 km = 3000 m (displacement of the ship)
[tex]\theta=0^{\circ}[/tex] (because the force is horizontal, and the displacement is horizontal as well)
Therefore, the work done on the ship is
[tex]W=(5.00\cdot 10^3)(3000)(cos 0^{\circ})=1.5\cdot 10^7 J[/tex]
Learn more about work:
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