Respuesta :
Answer:
v' = -0.25 m/s
Explanation:
given,
mass of the astronaut,M = 80 kg
mass of the oxygen tank, m= 10 Kg
speed at which tank is thrown, v= 2 m/s
using conservation of momentum
( M+ m ) u = M v' + m v
initial velocity of the system is zero
0 = 80 x v' + 10 x 2
v' =[tex]-\dfrac{20}{80}[/tex]
v' = -0.25 m/s
negative sign represent that the speed of the astronaut is in opposite direction to motion of cylinder.
Speed of the astronaut is equal to 0.25 m/s
Velocity is a vector quantity. The final velocity of the Astronaut-cylinder system is 0.25 m/s.
From the conservation of momentum:
[tex]( M+ m ) u = M v' + m v[/tex]
Where,
[tex]M[/tex]- mass of the astronaut = 80 kg
[tex]m[/tex]- mass of the oxygen tank = 10 Kg
[tex]v[/tex] - speed at which tank is thrown = 2 m/s
[tex]( M+ m ) u[/tex]- initial momentum = 0
Put the values in the formula,
[tex]0 = 80 \times v' + 10 \times 2\\\\v' = \dfrac {20}{80}\\\\v' = 0.25[/tex]
Therefore, the final velocity of the Astronaut-cylinder system is 0.25 m/s.
Learn more about conservation of momentum:
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