Answer:
Therefore the value of x is
[tex]x=1\pm\sqrt{19}i[/tex]
Step-by-step explanation:
Given:
[tex]x^{2}+20=2x[/tex] which is
[tex]x^{2}-2x+20=0[/tex]
To Find:
x = ? using Quadratic Formula
Solution:
For a Quadratic Equation ax² + bx + c = 0 , Formula Method is given as
[tex]x=\dfrac{-b\pm\sqrt{b^{2}-4ac}}{2a}[/tex]
On Comparing with above we get
[tex]a=1\\b=-2\\c=20[/tex]
Substituting a , b , c in Formula method we get
[tex]x=\dfrac{-(-2)\pm\sqrt{(-2)^{2}-4(1)(20)}}{2\times 1}\\\\x=\dfrac{2\pm\sqrt{-76}}{2}\\\\x=\dfrac{2\pm2\sqrt{19}i}{2}\\Dividing\ by\ 2\ we\ get\\\\x=1 \pm\sqrt{19}i[/tex]
Therefore the value of x is
[tex]x=1\pm\sqrt{19}i[/tex]
