Suppose a triangle has two sides of length 2 and 3 and that angle between these two sides is 60 degrees. What is the length of the third side

Respuesta :

Answer:

The measure of the third side is [tex]\sqrt{7}\ units[/tex]

Step-by-step explanation:

we know that

Applying the law of cosines

[tex]c^2=a^2+b^2-2(a)(b)cos(C)[/tex]

where

C is the angle between side a and side b

we have

[tex]a=2\ units\\b=3\ units\\C=60^o[/tex]

substitute

[tex]c^2=2^2+3^2-2(2)(3)cos(60^o)[/tex]

[tex]c^2=13-(12)(\frac{1}{2})[/tex]

[tex]c^2=13-6[/tex]

[tex]c^2=7[/tex]

[tex]c=\sqrt{7}\ units[/tex]

Answer: √7

Step-by-step explanation:

a p e x