Respuesta :
Volume can be defined as the capacity of a given container or object.
Dilution is the process of reducing the concentration of a given solution by adding more water to that solution.
The volume of distilled water that should be added to 10.0 mL of 6.00 M HCl(aq) in order to prepare a 0.500 M HCl(aq) solution is approximately 110ml
The formula to solve this question is given as;
C1V1 = C2V2
Where
C1 = Initial concentration of the solution
V1 = Initial volume of the solution
C2 = Fnal concentration of the solution
V2 = Final volume of the solution.
We know from the question that
C1 = 6M of HCl(aq)
C2 = 0.5M of HCl(aq)
V1 = 10ml of HCl
V2= Volume of distilled water.
Applying the formula:
6 M x 10 ml = 0.5M x V2
Divide both sides by 0.5M
V2 = 6 M x 10 ml/0.5M
V2 = 120 ml
The Volume of water added = Final volume -Initial volume
Final volume = 120 ml
Initial volume = 10 ml
Hence,
120ml - 10ml = 110ml
The volume of distilled water that should be added to 10.0 mL of 6.00 M HCl(aq) in order to prepare a 0.500 M HCl(aq) solution is approximately 110ml.
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Solution is defined as the mixture of two or more substance. In solution, the solute and solvent are present. The volume of solution in the given data is 110ml.
Volume can be defined as the capacity of the given container. The dilution is the process of reducing the concentration of the given solution by adding water.
Given that,
- Volume of HCl = 10 ml
- Concentration of HCl = 6 M HCl
From the formula:
C1V1 = C2V2
where,
- C1 = Initial concentration of the solution
- V1 = Initial volume of the solution
- C2 = Final concentration of the solution
- V2 = Final volume of the solution
Applying the formula:
- 6 M x 10 ml = 0.5 M x V2
Dividing both sides by 0.5 M, we get:
- [tex]\text{V}_2&= \dfrac{6 \;\text M}{0.05\;\text M}[/tex]
- V2 = 120 ml
Now, the volume required to added:
- Volume Required = Final volume -Initial volume
- Volume Required = 120 - 10
- Volume Required = 110 ml
Therefore, the volume required to prepare 0.5 M HCl is 110 ml.
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